D08cmdsubst.ztst   [plain text]


# Tests for command substitution.

%prep
  mkdir cmdsubst.tmp
  touch cmdsubst.tmp/file{1,2}.txt

%test
  foo="two words"
  print -l `echo $foo bar`
0:Basic `...` substitution
>two
>words
>bar

  foo="two words"
  print -l $(echo $foo bar)
0:Basic $(...) substitution
>two
>words
>bar

  foo='intricate buffoonery'
  print -l "`echo $foo and licentiousness`"
0:Quoted `...` substitution
>intricate buffoonery and licentiousness

  foo="more words"
  print -l "$(echo $foo here)"
0:Quoted $(...) substitution
>more words here

# we used never to get this one right, but I think it is now...
  print -r "`print -r \\\\\\\\`"
0:Stripping of backslasshes in quoted `...`
>\\

  print -r "$(print -r \\\\\\\\)"
0:Stripping of backslashes in quoted $(...)
>\\\\

  fnify() { print \"$*\"; }
  print `fnify \`fnify understatement\``
0:Nested `...`
>""understatement""

  print $(fnify $(fnify overboard))
0:Nested $(...)
>""overboard""

  fructify() { print \'$*\'; }
  print "`fructify \`fructify indolence\``"
0:Nested quoted `...`
>''indolence''

  print "$(fructify $(fructify obtuseness))"
0:Nested quoted $(...)
>''obtuseness''

  gesticulate() { print \!$*\!; }
  print $((gesticulate wildly); gesticulate calmly)
0:$(( ... ) ... ) is not arithmetic
>!wildly! !calmly!

  commencify() { print +$*+; }
  print "$((commencify output); commencify input)"
0:quoted $(( ... ) .. ) is not arithmetic
>+output+
>+input+

  (
  cd cmdsubst.tmp
  print first: ${$(print \*)}
  print second: ${~$(print \*)}
  print third: ${$(print *)}
  print fourth: "${~$(print \*)}"
  print fifth: ${~"$(print \*)"}
  )
0:mixing $(...) with parameter substitution and globbing
>first: *
>second: file1.txt file2.txt
>third: file1.txt file2.txt
>fourth: *
>fifth: file1.txt file2.txt

  $(exit 0) $(exit 3) || print $?
0:empty command uses exit value of last substitution
>3

  X=$(exit 2) $(exit 0) || print $?
0:variable assignments processed after other substitutions
>2

 false
 ``
0:Empty command substitution resets status

 false
 echo `echo $?`
0:Non-empty command substitution inherits status
>1